here is sample calculation( ideal case)
At hill climbing, tractive force available at an inclination of 45°,
F=Wsinθ- μWcosθ ≈2081N
Power =10hp=7460 Watt =F*V
So, our vehicle can climb the hill of inclination 45° with this velocity.
On a horizontal road,
Air resistance (Ra)= Ka*A*(V)²
Ka= 0.004725 – 0.005 ,depending upon type of vehicle we have considered it to be 0.005
Area (A) = Projected front area= 1.025 m²
Velocity = 59.06km/hr
Rolling Resistance (Rr) = K*W
W=total weight of vehicle= 300kg
K is a constant and depends upon the nature of surface
We have considered the road surface to be loose mud whose rolling resistance is 0.0435
Hence Rolling resistance (Rr) = 128.02N
Total resistance= Ra + Rr =145.9N
F= (Te* Gear ratio* Transmission efficiency)/wheel radius
Te=engine torque= 19Nm
Wheel radius = 0.3175m
Hence F=756.21N (at low speed)
So, 0-60 km/hr in 8.21 sec.
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